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## Counting working days

Hi

I have a table with a list of delivery dates for orders that have failed to go out. I need to report on how many working days these are passed that delivery date.

For example I have a table like this:

OrderNo, RequestedDeliveryDate

Order1  , 2012-08-27

Order2  , 2012-08-31

So if I was to run this today (2012-09-03) I need an output of:

OrderNo, RequestedDeliveryDate,DaysLate

Order1  , 2012-08-27                   , 5

Order2  , 2012-08-31                   , 1

Any help or direction on how to solve this will be a fantastic.

Thanks

4 REPLIES 4
Senior Supporter

## Re: Counting working days

How do you define "working days"?

Always Mo - Fr, Mo-Sa, exclude Holidays?

If you need to consider Holidays you would need a kalendar table to maintain these.

Fan

## Re: Counting working days

Hi ulrich,

Working days a Monday to Friday. I do not need to consider holidays.

Thanks.

Senior Supporter

## Re: Counting working days

so let's assume the following table

`create volatile table vt_datesas(select c1.calendar_Date from_dt, c2.calendar_date to_dtfrom sys_calendar.calendar c1     cross join     sys_calendar.calendar c2where c1.calendar_Date between  current_date - 30 and current_Date      and c2.calendar_Date between  current_date - 30 and current_Date        and c2.calendar_date > c1.calendar_date) with data primary index (from_dt)on commit preserve rows;`

You have two choices:

1. simple logic but join on calendar table

`select from_dt,        to_dt,        sum(case when c.day_of_week in (1,7) then 0 else 1 end) - (case when sum(case when c.day_of_week in (1,7) then 0 else 1 end) = 0 then 0 else 1 end) as count_of_weekdaysfrom vt_dates v     join sys_calendar.calendar c        on c.calendar_Date between v.from_dt and v.to_dtgroup by 1,2order by 1,2`

2. direct calculation with not too obvious formula

`select from_dt,        to_dt,        case when day_of_week(from_dt) = 7 then 2            when day_of_week(from_dt) = 1 then 1            else 0       end + from_dt as next_work_dt,       case when day_of_week(to_dt) = 7 then -1            when day_of_week(to_dt) = 1 then -2            else 0       end + to_dt as prev_work_dt,       (prev_work_dt - next_work_dt)+1 as diff,       (case when diff mod 7 = 0 then 1 else 0 end) as correct_fw,       (diff - diff mod 7) / 7 as full_week,       case when diff < 0             then 0             else diff - (full_week*2) - 1       end +        case when day_of_week(prev_work_dt) < day_of_week(next_work_dt)                  then -2             else 0        end +       case when diff mod 7 = 0 then 2 else 0 end       as num_of_weekdaysfrom vt_dates vorder by 1,2`

If your table is big and the number of workdays can also be big it might be worth to consider solution two.

A SQL UDF might be usefull to have a central logic for it - even if the UDF code becomes more unreadable due to repeating cases...

Fan

## Re: Counting working days

Hi ulrich,

Solution 1 works wonderfully.

Thanks so much this has solved somthing that has stumpt me for a while now.